From the sum of (4a2−7b2+9) and (−5a2+8b2−11), subtract (2a2+b2+1).
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Answer:
-3a²
Step-by-step explanation:
(4a²-7b²+9)+(-5a²+8b²-11)
= 4a²-7b²+9-5a²+8b²-11
= (-a²+b²-2)
subract (2a²+b²+1) from (-a²+b²-2)
=(-a²+b²-2)-(2a²+b²-2)
= -a²+b²-2-2a²-b²+2
= -3a²
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