Math, asked by kanika7a, 4 months ago

From the sum of 4x+2y-3z and 2x-4y+6z subtract the sum of 3z+4y-4 and 2y-4z+6

Answers

Answered by sumaiya298

1

Answer:

6x-8y+4z+2

Step-by-step explanation:

(4x+2y-3z+2x-4y+6z-[(4y+3z-4)+(2y-4z+6)]

6x-2y+3z-(6y-z+2)

6x-2y+3z-6y+z+2

6x-8y+4z+2

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