From the sum of 4x^4-3x^3+6x^2,4x^3+4x-4x and -3x^4-5x^2+2x subtract 5x^4-7x3-3x+4.
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[(4 + 3x) + (5 – 4x + 2x2)] – [(3x2 – 5x) + (x2 + 2x + 5)]
= 4 + 3x + 5 – 4x + 2x2 – 3x2 + 5x + x2 – 2x – 5 = 4 + 3x – 4x + 2x2 + 5 – 3x2 + x2 + 5x – 2x – 5 (re-arranging the terms)
= -x + 2x2 + 9 - 2x2 + 3x - 5 = 2x + 4
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here is your answer.i hope it will help you
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