Math, asked by Schoolbh, 5 hours ago

From the sum of 5y² + 7yz, -5y² – yz – z² and 4yz + 3z², subtract the sum of 5y² – 3z² and 8y² + yz – 6z²

Answers

Answered by savnijain6032
10

Step-by-step explanation:

Sum of 5y² + 7yz + (-5y² - yz - z²) + 4yz + 3z²

= 5y² + 7yz - 5y² - yz - z² + 4yz + 3z²

= 5y²- 5y² + 7yz + 4yz - yz - z² + 3z²

= 10yz + 2z²

Now sum of 5y² - 3z² + 8y² + yz - 6z²

= 5y² + 8y² - 3z² - 6z² + yz

= 13y² - 9z² + yz

Subtraction of both :

10yz + 2z² - (13y²- 9z² + yz)

= 10yz + 2z² - 13y² + 9z² - yz

= 10yz - yz + 2z² + 9z² - 13y²

= 9yz + 11z² - 13y²

May the answer will help you!!!

Answered by vaibhavandvedantchou
1

Answer:

Step-by-step explanation:

10yz - yz + 2z² + 9z² - 13y²

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