from the sum of 6+4y+y^2 and 8-5y+3y^2,subtract the sum of 6y^2-4y and -y^2+4y+9
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Answer:
answer:-2-y-y²
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Given:
Sum of: y²+4y+6 and 3y²-5y+8,
Sum of: 6y²-4y and -y²+4y+9
To Find:
Solve the above arithmetic equation:
Solution:
Sum of:
⇒ ( y²+4y+6) + (3y²-5y+8) =
⇒ 4y²-y +14
Sum of:
⇒ ( 6y²-4y ) + (-y²+4y+9)
⇒ 5y²+9
now subtract :
⇒ (4y²-y +14 ) -(5y²+9)
⇒ 4y²-y +14 - 5y²- 9
⇒ -y² - y +5
Hence, the final answer is - y² - y + 5 .
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