Math, asked by ikmankaur35, 19 days ago

From the sum of 6q2-6r2 and-8q2 +6qr+ 2r² subtract the sum of 8q2 + 2gr, -4q2-7gr-r²

Answers

Answered by pyneaishani
0

Answer:

6q2-5gr-3r

Step-by-step explanation:

sum of (6q2-6r2)+(-8q2 + 6qr + 2r squared)

= 6q2-8q2-6r2+6qr + 2r squared

=-2q2+2r squared

sum of (8q2 + 2gr)+(-4q2 -7gr-r squared)

=8q2-4q2+2gr-7gr-r squared

=4q2-5gr- r squared

subtract (4q2-5gr -r squared) - (-2q2+2r squared)

=4q2+2q2-5gr-r squared-2r squared

=6q2-5gr-3r squared

HOPE YOU UNDERSTAND .

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