Question

from the sum of 7+3x and 6-2x+x square, subtract the sum of 2x square-3x and 2x square +3x-9​

Answer 1

Answer:

$(7 + 3x + 6 - 2x + {x}^{2} ) - (2 {x}^{2} - 3x + 2 {x}^{2} + 3x - 9) =( {x}^{2} + x + 13) - (4 {x}^{2} - 9) = - 3{x}^{2} + x + 22$