Question

From the sum of 7+3x and 6-2x+x² subtract the sum of 2x² -3x and 2x²+3x-9.


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Answer 1

7+3x + 6-2x+x² = (7+6)+(3x-2x)+x²
=13+x+x² ------(I)
2x²-3x + 2x²+3x-9 =(2x²+2x²)+.
(-3x+3x)+(-9)
= 4x²-9 -----(II)
Subtracting (I) - (II)
13+x+x² - (4x²-9)
= 13+x+x²- 4x²+9
=(13+9)+x+(x²-4x²)
=22+x-3x²