Question

From the sum of (8a - 5b + 3) and (6a + 3b + 5) subtract the difference of (2a - 3b + 8) and (a + 2b+ 6)​

Answer 1

$8a-5b+3+6a+3b+5$$=14a-2b+8$

$2a-3b+8-a-2b-6=a-5b+2$

$14a-2b+8-a+5b-2=13a+3b+6$

so the ans is

$13a+3b+6$

Answer 2

As per data given in the question,

We have to determine the value when the sum of (8a - 5b + 3) and (6a + 3b + 5) is subtracted from the difference of (2a - 3b + 8) and (a + 2b+ 6)​

So, let us determine the sum of (8a - 5b + 3) and (6a + 3b + 5)

So, sum will be,

$(8a - 5b + 3) + (6a + 3b + 5)\\=> 8a - 5b + 3 + 6a + 3b + 5\\=>14a-2b+8$

And the the difference of (2a - 3b + 8) and (a + 2b+ 6)​ will be,

$(2a - 3b + 8) - (a + 2b+ 6)\\=>(2a - 3b + 8 - a - 2b- 6)\\=>a-5b+2$

Hence, the value when the sum of (8a - 5b + 3) and (6a + 3b + 5) is subtracted from the difference of (2a - 3b + 8) and (a + 2b+ 6)​ will be,

$(14a-2b+8) +(a-5b+2)\\=>15a-7b+10$