Question

from the sum of (9. + 3x) and (7-4x+2x²) subtract the sum of (3x²- 5x) and ( -x²+2x + 5)​

Answer 1

Answer:

= (9 + 3x) + (7 - 4x + 2x²)

= 9 + 3x + 7 - 4x + 2x²

= 16 - x + 2x²

again

= (3x² - 5x) + ( -x² + 2x + 5)

= 3x² - 5x - x² + 2x + 5

= 2x² - 3x + 5

now

=( 16 - x + 2x²) - (2x² - 3x + 5)

= 16 - x + 2x² - 2x² + 3x - 5

= 11 + 2x

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