Question

From the sum of 9x2 + 2xy - 5y2 and 2x2 – 3y subtract the sum of 3x2 - 5y2 and 12x2 – 5xy + 9y2​

Answer 1

Step-by-step explanation:

Here,

BOX1

$(9 {x}^{2} + 2xy - 5 {y}^{2}) +( 2 {x}^{2} - 3y) \\ = 11 {x}^{2} + 2xy -5 {y}^{2} - 3y$

BOX2

$(3 {x}^{2} - 5 {y}^{2} ) + (12 {x}^{2} - 5xy + 9 {y}^{2} ) \\ = 15 {x}^{2} - 5xy + 4 {y}^{2}$

SUBTRACTING BOX2 FROM BOX1, WE HAVE,

$(15 {x}^{2} - 5xy + 4 {y}^{2} ) - (11 {x}^{2} + 2xy - 5 {y}^{2} - 3y) \\ = 4 {x}^{2} - 17xy + 9 {y}^{2} - 3y \\ = 4 {x + 9 {y}^{2} }^{2} - 17xy - 13y$

THIS IS THE ANSWER

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