Math, asked by sujitsatpati27, 4 months ago

From the sum of :
a^2 − 7a + 10 and 3a^2+ 4a − 15,
Subtract 2a^2 + a − 9​

Answers

Answered by tanishkatanu831
2

Answer:

Answer:a²2-12a+4

Step-by-step explanation:

Sum of (a²2-7a+10) + (3a²2+4a-15)

= a²2-7a+10+3a²2-4a-15

= a²2+3a²2-7a-4a+10-15

= 3a²4-11a-5

Now,

Subtract (3a²4-11a-5) - (2a²2+a-9)

= 3a²4-11a-5-2a²2-a+9

= 3a²4 -2a²2-11a-a-5+9

= a²2-12a+4

Answered by TokyoLights
2

Answer:

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Step-by-step explanation:

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