From the sum of a + 2b - 1 and 3a - b
+ 6, subtract the sum of 9a + 3b - 1 and
- 2a - 5b - 2.
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Answer:
-3a+3b+8
Step-by-step explanation:
sum 1 = a+2b-1 + 3a-b+6
= 4a+b+5
sum 2 = 9a+3b-1 + -2a-5b-2
= 7a-2b-3
according to the ques,
subtracting sum 2 from sum 1,
= 4a+b+5 - (7a-2b-3)
= 4a+b+5 - 7a+2b+3
= -3a+3b+8
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