Question

from the sum of a² + 4b² - 6ab, b² + 6, a² - 4ab and a² - b² + 2ab substract -2a² + b² - ab + a​

Answer 1

Step-by-step explanation:

sum of 4 equation

a^ 2 + 4b ^ 2 - 6ab + b^ 2 + 6 + a^ 2 - 4ab + a^ 2 - b ^ 2 + 2ab

= a^ 2 + a ^ 2 + a ^ 2 + 4b ^ 2 + b ^ 2 - b ^ 2 - 6ab - 4ab +2ab

= 3a ^ 2 + 4b ^ 2 - 8ab

subtracting

3a ^ 2 + 4b ^ 2 - 8 ab - ( - 2a ^ 2 + b ^ 2 - ab + a )

= 3a^2 + 2a^2 + 4b ^ 2 - b ^ 2 - 8ab + ab + a

= 5 a^ 2 + 3b ^ 2 - 7ab + a

that is your answer

hope it is useful for you

Answer 2

Answer:

5a²+3b²-7ab-a+6

Step-by-step explanation:

first find the sum

a²+4b²-6ab+b²+6+a²-4ab+a²-b²+2ab

=a²+a²+a²+4b²+b²-b²-6ab-4ab+2ab+6

=3a²+4b²-8ab+6

find the difference

(3a²+4b²-8ab+6)-(-2a²+b²-ab+a)

=3a²+4b²-8ab+6+2a²-b²+ab-a

=3a²+2a²+4b²-b²-8ab+ab+6-a

=5a²+3b²-7ab-a+6