Question

from the sum of b²-3c² and b²+6bc-c² subtract the sum of 2b²-bc-c² and 4c²+bc-b²​

Answer 1

Answer:

b²-7c²+6bc

Step-by-step explanation:

(b²-3c²+b²+6bc-c²)-(2b²-bc-c²+4c²+bc-b²)

= (2b²-4c²+6bc)-(b²+3c²)

= 2b²-4c²+6bc-b²-3c²

= b²-7c²+6bc