Question

from the sum of l-m+2n,3l-2m+n and 4l+5m-6n, subtract the sum of l+m+n and 2l+3m+4n​

Answer 1

Answer:

Firstly, we shall do the sum of l-m+2n and 3l-2m+n

$= \sf \: l - m + 2n + 3l - 2m + n$

$= \sf \: l + 3l - m - 2m + 2n + n$

$= \sf \: 4l - 3m + 3n$

Then, sum of l+m+n and 2l+3m+4n

$= \sf \: l + m + n + 2l + 3m + 4n$

$= \sf \: l + 2l + m + 3m + n + 4n$

$= \sf \: 3l + 4m + 5n$

${}$

Now, subtracting the sum of l+m+n and 2l+3m+4n from the sum of l-m+2n and 3l-2m+n we will get,

${}$

$= \sf \: 4l - 3m + 3n - (3l + 4m + 5n)$

$= \sf \: 4l - 3m + 3n - 3l - 4m - 5n$

$= \sf \: 4l - 3l - 3m - 4m + 3n - 5n$

$= \sf \: l - 7m - 2n$

Therefore the required answer is l-7m-2n

Answer 2

Answer:

$\huge{\underline{\bold{\orange{Question–}}}}$

From the sum of l-m+2n,3l-2m+n and 4l+5m-6n, subtract the sum of l+m+n and 2l+3m+4n

Step-by-step explanation:

‌$\huge\fbox\red{Answer}$

‌l - 7m -2n