Question

From the sum of p3 + q3 -3pq + p2q and 3p -q + 2pq + p2q subtract 3p3 - 4q3​

Answer 1

Answer:

p3+q3-3pq+p2q+3p-q+2pq+p2q

=p3 + q3+2p2q-pq+3p-q ...............eq(1)

3p3-4q3 .................eq (2)

subtracting eq(2) from (1)

p3+ q3+2p2q-pq+3p-q - ( 3p3 - 4q3)

p3 +q3+2p2q-pq+3p-q-3p3 +4q3

= -2p3+5q3+2p2q- pq+3p-q

Step-by-step explanation:

p3+q3-3pq+p2q+3p-q+2pq+p2q

=p3 + q3+2p2q-pq+3p-q ...............eq(1)

3p3-4q3 .................eq (2)

subtracting eq(2) from (1)

p3+ q3+2p2q-pq+3p-q - ( 3p3 - 4q3)

p3 +q3+2p2q-pq+3p-q-3p3 +4q3

= -2p3+5q3+2p2q- pq+3p-q