Question

from the sum of three a square + 5 a b minus 7 b square and 11 a square minus 6 a b + 2 b square ​

Answer 1

Answer:

$14 {a}^{2} - ab - 5 {b}^{2}$

Step-by-step explanation:

$(3 {a}^{2} + 5ab - 7 {b}^{2}) + (11 {a}^{2} - 6ab + 2 {b}^{2} \\ = 3 {a }^{2} + 11 {a}^{2} + 5ab - 6ab + (2 { b}^{2} - 7 {b}^{2} ) \\ = 14 {a}^{2} + ab - 5 {b}^{2}$