Question

From the sum of x∧2 – 2xy + y∧2 and 2x∧2 + 3xy –3y∧2 subtract 3x∧2 – xy + y∧2

Answer 1

Answer:

2xy-3y^2

Step-by-step explanation:

=x^2-2xy+y^2+2x^2+3xy-3y^2-(3x^2-xy+y^2)

=x^2-2xy+y^2+2x^2+3xy-3y^2-3x^2+xy-y^2

=2xy-3y^2

Answer 2

Answer:

$- \frac{11}{3} {x}^{2} + \frac{7}{2} xy + \frac{11}{2} {y}^{2}$