Question

from the sum of x^2- 2xy + y^2 and x^2+ 2xy + y^2 subtract x^2-4xy + 4y^2​

Answer 1

hope it will help you:-)

Answer 2

Step-by-step explanation:

$According\: to \:question\:,$

$= ( {x}^{2} - 2xy + {y}^{2} ) + ( {x}^{2} + 2xy + {y}^{2} ) - ({x}^{2} - 4xy + 4 {y}^{2} ) \\ =( {x}^{2} + {x}^{2} ) + ( - 2xy + 2xy) + ( {y}^{2} + {y}^{2} ) - (x {x}^{2} - 4xy + 4 {y}^{2} ) \\ = 2 {x}^{2} + 2 {y}^{2} - ( {x}^{2} - 4xy + 4 {y}^{2}) \\ = 2 {x}^{2} + 2 {y}^{2} - {x}^{2} + 4xy - 4 {y}^{2} \\ = (2 {x}^{2} - {x}^{2} ) + (2 {y}^{2} - 4 {y}^{2} ) + 4xy \\ = {x}^{2} - 2 {y}^{2} + 4xy \\ \\ \\ \\ I \: hope \: you \: like \: it \: and \: mark \: brainliest \: answer \: .$