From the sum of x+y? -6, -* + 5y + 11 and 4x + 10, subtract the sum of y' +15 and 2x - y.
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Answer:
=[(3x−y+11)+(−y−11)]−[(3x
2
−5x)+(−x
2
+2x+5)]
=[3x−y+11−y−11]−[3x
2
−5x−x
2
+2x+5]
=[3x−2y]−[2x
2
−3x+5]
=3x−2y−2x
2
+3x−5
=−2x
2
+6x−2y−5
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