Question

From the sum of x²+3y²-6xy,2x²-y²+8xy+y²+8and x²-4xy subtract the sum of -3x²+4y²+3 and 4y²-5.​

Answer 1

Step-by-step explanation:

(x²+3y²-6xy+2x²-y²+8xy+y²+8+x²-4xy) -(3x²+4y²+3+4y²-5)

=(4x²+3y²-2xy+8)-(3x²+8y²-2)

= (4x²+3y²-2xy+8)-(3x²-8y²+2)

=4x²+3y²-2xy+8-3x²-8y²+2

=x²-5y²-2xy+10

Answer 2

Answer:

Answer Will be (6x^2 - 5y^2 +2xy+10)

Step-by-step explanation:

ATQ,

(x²+3y²-6xy+2x²-y²+8xy+y²+8) - (-3x²+4y²+3+ 4y²-5)

= (3x^2+3y^2+2xy+8)-(-3x^2+8y^2-2)

=(3x^2 + 3y^2 +2xy+8+3x^2-8y^2+2)

=(3x^2+3x^2+3y^2-8y^2+2xy+8+2)

=(6x^2-56^2+2xy+10) [Ans]