Math, asked by aarya2901, 4 days ago

From the sum of x2 + 4y2 – 6xy, x2 – y 2 + 2xy and x2 – 4xy, subtract –2x2 + y2 – xy.

Answers

Answered by vishalns1994
0

Answer:

The simplified equation is 4x²+2y²-3xy

Step-by-step explanation:

Given : Three equations (x² + 4y² – 6xy), (x² – y ² + 2xy) and

             (–2x² + y² – xy )

            We have to add first two and substract third equation

Solution : (x² + 4y² – 6xy) + (x² – y ² + 2xy) - (–2x² + y² – xy )

           Opening the brackets we get

            = x² + 4y² – 6xy + x² – y ² + 2xy +2x² - y² + xy  

        Rearranging the like terms

         = x² +x²+2x²+ 4y²– y ² - y²– 6xy+ 2xy+ xy

         = 4x²+2y²-3xy

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