from the sum of x² - y² - xy and 3x² - 2y² + 7 subtract 2x² + 2y² + 7x²y - 3xy²
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Answer:
Sum of 3x2 - 2x and 3x + 7
= (3x2 - 2x) + ( 3x +7)
= 3x2 - 2x + 3x + 7
= (3x2 + x + 7)
Now, required expression = (2x2 - 3x + 1) + (3x2 + x + 7)
= 2x2 + 3x2 - 3x + x + 1 + 7
= 5x2 - 2x + 8
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1
Step-by-step explanation:
x^2 - y^2 - xy + 3x^2 - 2y^2 + 7 - 2x^2 +2y^2 + 7x^2y - 3xy^2
= 4x^2 - 3y^2 - xy + 7 - 2x^2 + 2y^2 + 7x^2y - 3xy^2
= 2x^2 - y^2 - xy + 7 + 7x^2y - 3xy^2
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