Question

from the sum of x²+yz,-y²+yz-z² and yz +2z² , subtract the sum of 3y²-z² and -y²+yz-2z²​

Answer 1

Answer:

Your Answer = x² - 3y² + 4z² + 2yz

Step-by-step explanation:

The sum of (x² + yz) , (-y² + yz - z²) and (yz + 2z²)

=> x² + yz - y² + yz - z² + yz + 2z = Sum 1

=> Sum 1 = x² - y² + z² + 3yz

The sum of (3y² - z²) and (-y² + yz - 2z²)

=> Sum 2 = 3y² - z² - y² + yz - 2z²

=> Sum 2 = 2y² - 3z² + yz

According to your Question : -

Your Answer (Y.A.) = Sum 1 - Sum 2

(Y.A.) = (x² - y² + z² + 3yz) - (2y² - 3z² + yz)

(Y.A.) = x² - y² + z² + 3yz - 2y² + 3z² - yz

(Y.A.) = x² - 3y² + 4z² + 2yz

Hope it helps u !!!!!!!

Please mark my answer as the brainliest answer.