Question

from the sum of x³+3y²-6xy,y²+8and 2x²-y²+8xy,subtract the sum of-3x²+4y²+xyand 6x²-y²+7xy-5.​

Answer 1

Answer:

$A-B = x^{3}-7x^{2}-6xy+13$

Step-by-step explanation:

The sum of  $(x^{3}+3y^{2}-6xy)$, $y^{2}+8$, and ($2x^{2} -y^{2} + 8xy$) is-

$A = (x^{3}+3y^{2}-6xy)+(y^{2}+8)+(2x^{2}-y^{2}+8xy)$

$A = x^{3}+x^{2}+(3y^{2}+y^{2}-y^{2}+(8xy-6xy)+8$

$A = x^{3}+2x^{2}+3y^{2}+2xy+8$

The sum of $(3x^{2}+4y^{2}+xy) \ and \ (6x^{2}-y^{2}+7xy-5)$ is-

$B = (3x^{2}+4y^{2}+xy)+(6x^{2}-y^{2}+7xy-5)$

         = $(3x^{2}+6x^{2})+(4y^{2}-y^{2}) +(xy+7xy) - 5$

$B = 9x^{2}+3y^{2}+8xy-5$

Now, $A -B = (x^{3}+2x^{2}+3y^{2}+2xy+8)-(9x^{2}+3y^{2}+8xy-5)$

                   = $x^{3}+2x^{2}+3y^{2}+2xy+8-9x^{2}-3y^{2}-8xy+5$

                   =$x^{3}+(2x^{2}-9x^{2})+(3y^{2}-3y^{2})+(2xy-8xy)+(8+5)$ $A-B = x^{3}-7x^{2}-6xy+13$

Answer 2

x squared +3y2-6xy

y2. +8

2x2-y2+8xy

-3x2+4y2+X

6x2-y2+7xy-5

3x2+3y2+8xy-5

X3+2x2+3y2+2xy+8

(X3+2x2+3y2+2xy+8

=X3+2x2+3y2+2xy+8-3x2-3y2+8xy+5

=x3-x2-6xy+13 Ans

Hope it helps you