Question

from the sum of13xy answer me.​

Answer 1

Answer:

y²-3x²-12xy

Step-by-step explanation:

[(3y²-x²)+(-y²+2xy-x²)]-[(13xy+2y²)+(-y²-xy-x²)+(2x²+12xy)]

=[3y²-x²-y²+2xy-x²]-[13xy+2y²-y²-xy-x²+2x²+12xy]

=[2y²-2x²+2xy]-[14xy+y²+x²]

=2y²-2x²+2xy-14xy-y²-x²

=y²-3x²-12xy

Answer 2

Answer:22xy-y^2+3x^2

Explanation: sum 1-
13xy+2y^2-y^2-xy-x^2+2x^2+12xy
=(13+12-1)xy+(2-1)y^2+(-1+2)x^2
=24xy+y^2+x^2

Sum 2-
3y^2-x^2-y^2+2xy-x^2
=(3-1)y^2+(-1-1)x^2+2xy
=2y^2-2x^2+2xy

Now,sum 1-sum 2

Subtraction:
=(24xy+y^2+x^2)-(2y^2-2x^2+2xy)
=24xy+y^2+x^2-2y^2+2x^2-2xy
=(24-2)xy+(1-2)y^2+(1+2)x^2
=22xy-y^2+3x^2