Question

from the sum sum of 11x²-3y+8and 2x³+12y²+1,sudtract the sum of 9x³+y²-1 and 3x²+3y²+18​

Answer 1

Step-by-step explanation:

First we will find out the sum of

11x3−3y2+8 and 2x3+12y2−1

11x3−3y2+8+ 2x3+12y2−1

13x3+9y2+7

Now, we will find out the sum of

9x3+y2−1 and 3x3+3y2+18

9x3+y2−1 + 3x3+3y2+18

12x3+4y2+17

Now, subtract 12x3+4y2+17 from 13x3+9y2+7

we get,

13x3+9y2+7

12x3+4y2+17 --- x3+5y2−10Hence the required answer is x3+5y2−10.

Regards

rishita

Was this answer helpfulp