Question

from the surface of the earth and on beserta
ng is the acceleration due to gravity at a dent
IS 'S then among the following our one​

Answer 1

Answer:

Hello Dear.

Here is your answer---

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For the Earth,

 Let the Mass of the Earth be m and the radius of the earth be r.

Acceleration due to the gravity on Earth = g

Using the Formula,

                              g = Gm/r² --------------------------eq(i)

    

     Where G = Gravitation constant

                     = 6.67 × 10⁻¹¹ Nm²/kg² 

For the Another Planet,

 

  Mass = 4 × Mass of the earth

 Mass = 4 × m

Radius = 2 ×Radius of the Earth

           = 2 × r

Acceleration due to the Gravity = ng

 Now again using the formula,

  

  Acceleration due to gravity = G × Mass/Square of the radius

 

            

           ⇒ ng = G × 4m/(2r)²

                 ng = G × 4m/4r²

                  ng = G × m/r² -------------------------------eq(ii)

Putting the Value of g from eq(i) in the above equation,We get,

      n × (G × m/r²) = G × m/r²

          ⇒ n = 1

Thus, the value of n is 1.

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Hope it helps.

Have a Marvelous Day.