from the top of 10 m high building the angel of evaluation of the top of the tower is 45 and and the angle of depression of its foot is 30 determine the height of the tower
Answers
Step-by-step explanation:
The given scenario is shown in the attached figure.
Given:
DE=10
∠CDB=45
o
∠CDA=60
o
To find: AB
Solution:
tan∠CDB=
CD
CB
⇒tan45
o
=
CD
DE
∵CB=DE
1=
CD
10
CD=10 m
tan∠CDA=
CD
CA
⇒tan60
o
=
10
CA
3
=
10
CA
CA=10
3
m
AB=AC+BC
AB=10+10
3
≈27.32 m
Hence, the height of the tower is 27.32 m
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Step-by-step explanation:
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