Question

from the top of 120 m high light house the angle of depression of two ships on opposite side of the base of the light house is 30 degrees and 60 degrees what is the distance between the ship

Answer 1

Answer:

hope the attachment clears your doubts

Answer 2

Answer:

$\huge{\red{\boxed{\boxed{\green{\sf{CD=160\sqrt{3}m}}}}}}$

Step-by-step explanation:

$\huge{\red{\boxed{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}}$

□Height of light house=120m

To find:

○Distance between two ships:

$IN \triangle \: ABD\\ \tan30 \degree = \frac{p}{b} \\ \frac{1}{ \sqrt{3} } = \frac{AB}{BD} \\ \frac{1}{ \sqrt{3} } = \frac{120}{BD} \\ \therefore \: BD= {120} \sqrt{3} = 120 \sqrt{3} m \\ \\ IN \triangle \: ABC \\ \tan60 \degree = \frac{AB}{BC} \\ \sqrt{3} = \frac{120}{BC} \\ \therefore \: BC= \frac{120}{ \sqrt{3} } = 40 \sqrt{3} m \\ \\ > > distance \: between \: two \: ships \\ CD= BD+BC \\ CD= 120 \sqrt{3} + 40 \sqrt{3} \\CD = 160\sqrt{3} m$

$\huge{\red{\boxed{\boxed{\green{\sf{CD=160\sqrt{3}m}}}}}}$

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