Question

from the top of 7 M high building the angle of elevation of the top of a cable Tower is 60°degree and the angle of depression is of its foot is 45° determine the height of the tower

Answer 1

After cal AB is
$7 \sqrt{3}$
And total ht of tower is AB +BC =
$7 \sqrt{3 } + 7$
Hence
$7( \sqrt{ 3} + 1)$

Answer 2

$\textbf{Answer is in Attachment !}$