Question

from the top of a 10m high
building the angle of elevation of
a tower is 60 and the angle of
depression of its foot is 45 Determine
the height of the tower​

Answer 1

Answer:

=> Height if the tower is 10(1+√3) = 10(1+1.717) = 10×2.171 = 21.71 m

Step-by-step explanation:

=> By diagram ,

Let the height of tower = (h +10) m

Let the distance between building and tower be x m

By tangent form,

=> tan 45 = 10/x

=> x = 10/tan45

=> x = 10/1 = 10 m

Again ,

=> tan 60 = h/x

=> √3 = h/10

=> h = 10√3 m

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Hence , height of the tower is =(10+10√3)

= 10 (1+√3) m