Question

From the top of a 120m high tower a man observed two cars on opposite sides of the tower and in straight lines with the

base of the tower with angles of depression as 600 and 450

. Find the distance between the two cars.​

Answer 1

Answer:

189.28 meters

Step-by-step explanation:

height of the tower = 120 m

first car at the distance of x m

angle of depression to first car = 60°

tan 60° = √3 = 120/x

$x = \frac{120}{ \sqrt{3} } \\ x = \frac{120}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ x = \frac{120 \sqrt{3} }{3} \\ x = 40 \sqrt{3} \\ x = 69.28m$

second car is at distance of y mts

angle of depression to second car = 45°

tan 45° = 1

$1 = \frac{120}{y} \\ y = 120m$

distance between the cars = x + y

69.28 + 120 = 189.28 mts

Hope you get your answer