From the top of a 15m high building, the angle of elevation of the cable tower is 60 and the angle of depression of its foot is 30. determine the height of the tower
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let ground be y and
excess height of tower from the building be x,
so,
tan60= x/y=root3
or,
x=yroot3 ------ 1
tan30=15/y= 1/root3
or,
y= 15root3 ----------- 2
Substituting 2 into 1,
x= 15root3 x root3
=15x3
=45m
total height of tower= 45+15m
=60m
excess height of tower from the building be x,
so,
tan60= x/y=root3
or,
x=yroot3 ------ 1
tan30=15/y= 1/root3
or,
y= 15root3 ----------- 2
Substituting 2 into 1,
x= 15root3 x root3
=15x3
=45m
total height of tower= 45+15m
=60m
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