Question

From the top of a 7 m high building the angle of elevation of the top of the tower is 60 and the angle of depression of its foot is 45. find the hight of the tower.

Answer 1

As it is given that angle of elevation is from the top of 7M high building
given :-
angle of elevation which is taken as Angle AEB = 60
angle of depression which is taken as angle EDC = 45
Proof :-
first of all in triangle EDC
tan45= ED/DC
1/1=7/DC
DC is parallel and distance between two buildings is same so take EB as 7 M

Now, In triangle AEB
Tan 60= AB/BE
underoot 3 = H/ 7
7underoot 3 = H
now add 7underoot3 With seven as given in fig

Answer 2

$\textbf{Answer is in Attachment !}$