Question

From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the

angle of depression of its foot is 45°. Determine the height of the tower.​

Answer 1

In ΔABE,

$tan \: 60°= \frac{h}{AB}$

$h = AB \sqrt{3}....(1)$

In ΔABC,

$tan \: {45}^{°} = \frac{7}{AB}$

AB=7....(2)

By equation (i) and equation (ii)

h=7√3

So, height of tower is =h+7=7(√3+1)