from the top of a 7 meter high building the angle of elevation of the top of a cable Tower is 60° and the angle of depression of its foot is 45°. determine the height of the tower
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Let AB be the building and CD be the tower such that <EAD = 60o and <EAC = <ACB = 45o
Now, In triangle ABC, tan 45 = 1 = AB/BC
So, AB = AE = 7 m
Again in triangle AED,
tan 60 = root 3 = DE/AE
So, DE= AE.root3 = 7 . root3 m
Height of the cable tower = h + 7 = 7 root 3 m+ 7 m = 7 (1+ root3) m
,
Now, In triangle ABC, tan 45 = 1 = AB/BC
So, AB = AE = 7 m
Again in triangle AED,
tan 60 = root 3 = DE/AE
So, DE= AE.root3 = 7 . root3 m
Height of the cable tower = h + 7 = 7 root 3 m+ 7 m = 7 (1+ root3) m
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