from the top of a 70m tall tower, the angle of depression of the top and the base of a pole are found to be 30 and 45 respectively .Find the distance of the pole from the tower and the height of the pole.
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Answer:
Pole=CD
Tower=AB
since,inΔABC,∠AVB=45
0
∴ΔABCis45
0
−45
0
−90
0
triangle
∴AB=BC=70m
inrighttriangleAED
ΔAEDis30
0
−60
0
−90
0
triangle
ED
AE
=
3
1
∴AE=
3
70
∴BE=AB−AE=70−
3
70
=29.5854m.
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