From the top of a building 12 m high, the angle of depression of a car on the ground is
observed to be 30°. Find the distance of the car from the building.
Answers
Answered by
4
Answer:
Given,
height of the building=12m
angle of depression=30°
distance between car and building=?
it means adj side we don't know
apply tan
tan theta=opp/adj
tan30°=12/x
1/√3=12/x
x=12√3
Answered by
2
Answer:
given that
AB=12m
and angle of depression of car is 30 degree
so
tan30=1/root3
tan30=AB/BC
1/root3=12/BC
BC=12root3 metre
Step-by-step explanation:
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