CBSE BOARD X, asked by sajjanjayashree, 11 months ago

From the top of a building 15m high, the angle of elevation of the top of a tower is found to be 30 degree. From the bottom of the same building, the angle of elevation of the tower is found to be 45 degree. Determine the height of the tower and the distance between the tower and the building.

Answers

Answered by krishna190975
1

You can determine the ans. By making img. The distance between tower is 15metre and the height of the tower is1/√3 = x+15/15 =15=x√3+15         =x=15-15√3/√3                

Answered by shruti1234567
0

Tan 30degree =X/y

tan 30=1 /√3

1/√3=X/y

y=√3x

tan 45 =degree = x+15/ y

tan 45 =1

1= X+15/y

y=X+15

√3x=X+15

√3(x-1) =15

x-1=15/√3×√3/√3

x-1=15√3/3

x-1=5√3

X=6√3 ..

hope this answer will help u ..

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