Question

From the top of a building 40 m tall a boy projected a stone vertically upwards with an initial velocity of 10m\s. after how long will it pass through the point from where it was projected ?(take g=10m/s²)

Answer 1

S=-40m, u=10m/s, a=-10m/s2 By formulae s=ut+1/2 at2 -40=10×t +1/2 ×-10 ×t2 -40=10t-5t2 5t2-10t+40 On simplifying We get t2-2t+8 On simplifying We get Time t=4s

Answer 2

Answer:

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