Question

From the top of a building 50m high, the angle of depression of a car is 55 degrees. Find the distance of the car from the foot of the building

Answer 1

Step-by-step explanation:

tan55degree= hight of building/distance of building from the car

1.44=50/d

d=34.77m

Answer 2

The given question is

From the top of a building 50m high, the angle of depression of a car is 55 degrees. Find the distance of the car from the foot of the building.

The height if the building is 50 m.

The angle of depression of a car is 55°.

we have to find the distance of the car from the foot of the building.

the diagram clearly explains the solution

we have to find the value of x.

tan 55°= height of the building÷ Distance of the building from car.

tan 55°=1.44.

$1.44 = \frac{50}{d} \\ d = \frac{50}{1.44} \\ = 34.72m$

Therefore, the final answer is 34.72m

#spj2

Answer 3

The given question is

From the top of a building 50m high, the angle of depression of a car is 55 degrees. Find the distance of the car from the foot of the building.

The height if the building is 50 m.

The angle of depression of a car is 55°.

we have to find the distance of the car from the foot of the building.

the diagram clearly explains the solution

we have to find the value of x.

tan 55°= height of the building÷ Distance of the building from car.

tan 55°=1.44.

$1.44 = \frac{50}{d} \\ d = \frac{50}{1.44} \\ = 34.72m$

Therefore, the final answer is 34.72m

#spj2