Question

from the top of a building 60m height the angle of prepration of the top and the botton of a tower are abserved to be 30° and 60° find the height of the tower ​

Answer 1

see required figure on attachment

Let AC be the tower and BE be the building. Let height of the tower be h m. It is given that the angles of depression of the top C and bottom A of the tower, observed from top of the building be 30° and 60° respectively. Hence, the height of the tower is 40 m.

Answer 2

Answer:

Let AC be the tower and BE be the building. Let height of the tower be h m. It is given that the angles of depression of the top C and bottom A of the tower, observed from top of the building be 30° and 60° respectively. Hence, the height of the tower is 40 m.

Step-by-step explanation:

in △ADE

tan60

o

=

DE

60

⇒DE=

3

60

=20

3

and we can see that , BCDE is a rec\tan gle

so, BC=DE⇒BC=20

3

and BD=CE.......(1)

and in △ABC

tan30

o

=

20

3

AB

⇒AB=20

3

×

3

1

=20

Now, as AD=AB+BD⇒60=20+BD⇒BD=40

and from (1)

BD=CE=40 (which is the height of the Building)

Therefore, Answer is 40