From the top of a building 80 m high, a ball is thrown horizontally which hits the ground at a distance. The line joining the top of the building to the point where it hits the ground makes an angle of 450 with the ground. Initial velocity of projection of the ball is 10n then n = (g =10 m/s2)
Answers
Answer:the awnser ur looking for is 20 m/s.thatmeans 2*10.therefore n=2
n = 2
Explanation:
Building height = 80 m
The line joining the top of the building to the point where it hits the ground makes an angle of 45°
Tan 45° = Height of building / horizontal Distance
=> 1 = 80/ horizontal distance
=> horizontal Distance = 80 m
Velocity = 10 n
Time taken to cover 80 m horizontally = 80/10n = 8/n sec
Time taken to cover 80 m vertically = 8/n sec
S = ut + (1/2)at²
S = 80 m u = 0 a = g = 10 m/s²
0 + (1/2)(10)(8/n)² = 80
=> (8/n)² = 16
=> 8/n = 4
=> n = 8/4
=> n = 2
n = 2
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