From the top of a building of height 500m an object is dropped then find the velocity of the object when it reach to the earth .
Answers
Answered by
1
s = 500 m
v= ? , u =0 ,A= 10m/s²( g)
by v² = u²+2as
v² = 0²+2(10)(500)
v = 100 m/s
v= ? , u =0 ,A= 10m/s²( g)
by v² = u²+2as
v² = 0²+2(10)(500)
v = 100 m/s
Answered by
3
t ~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
TAKE ACCELERATION =10
INITIAL VELOCITY =0
S=500m
use formula
v^2=u^2+2as
v^2=0 + 2 x 10 x 500
v =underroot of 10000
v=100m/s
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
TAKE ACCELERATION =10
INITIAL VELOCITY =0
S=500m
use formula
v^2=u^2+2as
v^2=0 + 2 x 10 x 500
v =underroot of 10000
v=100m/s
HOPE IT WILL HELP YOU
Similar questions