Question

From the top of a cliff 50m above sea level, a stone is thrown vertically upwards with a velocity of 15m/s. After how many seconds and with what velocity will it hit the sea?(take g=10m/s)city

Answer 1

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d0793403c8de9a0ecace933e8a29201a.docx

Answer 2

Given : From the top of a cliff 50m above sea level, a stone is thrown vertically upwards with a velocity of 15m/s.

To Find : After how many seconds and with what velocity will it hit the sea

Solution:

S = ut + (1/2)gt²

S = 50 m

u = -15 m

g = 10  m/s²

50 = -15t  + (1/2)*10t²

=> 5t² - 15t - 50 = 0

=> t² - 3t - 10 = 0

=> (t - 5)(t + 2) = 0

=> t = 5   as time can not be negative

Hence after 5 secs     it hit the sea

v = u + at

v = -15 + 10 * 5

v= 35 m/s

It will git with a velocity of 35 m/s

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