Question

From the top of a cliff 60 m high, the angles of depression of two boats are 30" and 60"
respectively. Find the distance between the boats, when the boats are :
(i) on the same side of the cliff,
(ii) on the opposite sides of the cliff.
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Answer 1

Answer:

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Answer

Initial Velocity (u) = 80 m/s

Final Velocity (v) = 40 m/s

Acceleration (a) = -20 m/s² (Since the aircraft decelerates, the acceleration will be negative)

Distance travelled (s) = ?

We'll apply the third equation of motion for the given question.

3rd Equation of Motion ⇒ v² - u² = 2as

Substitute the variables and find the value of 's' (Distance)

⇒ (40)² - (80)² = 2(-20)(s)

⇒ 1600 - 6400 = -40s

⇒ -4800 = -40s

⇒ s = -4800 ÷ -40

⇒ s = 120 m

∴ The total distance travelled on the runway is 120 m.

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Additional Information

Acceleration is the rate of change of velocity in a particular given time.

We have 3 Equations of Motion. They are -:

1st Equation of Motion → v = u + at

2nd Equation of Motion→ s = ut+\dfrac{1}{2}at^{2}s=ut+

2

1

at

2

3rd Equation of Motion → v² - u² = 2as

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Answer 2

Answer

i) on the opposite side of the cliff

Step-by-step explanation:

hope this answer help you