From the top of a cliff the angles of depression of the top and the bottom of a tower 20mt. height were found to be 30°and 45°respectively. find the height of the cliff correct to 2 places of decimal.
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let h be the height of the cliff and d be the distance between cliff and tower. Then
tan 45 = h/d
1=h/d
h=d ....(1)
tan30 = (h-20)/d
1/√3=(h-20)/d
d=√3(h-20) put d=h from (1)
h=√3h-20√3
√3h-h=20√3
h(√3-1)=20√3
h=20√3/(√3-1)=20√3(√3+1)/((√3-1)(√3+1))
=20√3(√3+1)/(3-1)=10√3(√3+1)
√3=1.733
h = 10×1.732×2.732 = 47.32 Ans
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