from the top of a cone of a base of radius 24cm and height 45cm . a cone of slant height 17cm is cut off. what is the volume of the remaining frustum of the cone
Answers
Answer:
First find solutions the first step to find slant height and then volume of frustum + volume of cone to get the answer solve it
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The volume of remaining frustum of the cone = 26148.6 cm³
r1 = radius of the original cone = 24 cm
r2 = radius of the cone cut off
l1 = slant height of the original cone = √(2601) = 61 cm
l2 = slant height of the cone cut off = 17 cm
h1 = height of the original cone = 45 cm
h2 = height of the cone cut off
For the cone and the frustum
=> l1/l2 = r1/r2
=> r2 = 24 × (17/61)
=> r2 = 8 cm
h2 = √((l2)² - (r2)²)
h2 = √225 = 15 cm
The volume of the original cone = π/3 × (r1)² h1
= (1/3) × (22/7) × (24)² × 45
= 27154.3 cm³
The volume of the cone cut off = π/3 × (r2)² h2
= (1/3) × (22/7) × (8)² × 15
= 1005.7 cm³
The volume of frustum = volume of original cone - volume of the cone cut off
= 27154.3 - 1005.7
= 26148.6 cm³